Chart a python program for the quadratic type x^2-5x+6=0 findings its roots.

 import math

def solve_quadratic(a, b, c):

    # Calculate the discriminant

    discriminant = b**2 - 4*a*c

    

    if discriminant < 0:

        return "No real roots"

    elif discriminant == 0:

        # One real root

        root = -b / (2*a)

        return (root,)

    else:

        # Two real roots

        root1 = (-b + math.sqrt(discriminant)) / (2*a)

        root2 = (-b - math.sqrt(discriminant)) / (2*a)

        return (root1, root2)

# Coefficients for the equation x^2 - 5x + 6 = 0

a = 1

b = -5

c = 6

# Solve the equation

roots = solve_quadratic(a, b, c)

print(f"The roots of the equation {a}x^2 + ({b})x + {c} = 0 are: {roots}")